Question

A bird of 2 kg is flying with a constant velocity of (2i - 4j) m/s and another bird of 3 kg with (2i + 6j) m/s. Then the velocity of centre of mass of the system of two birds is .......... m/s.
(A) 2i + 5.2j
(B) 2i + 2j
(C) 2i - 2j
(D) 10i + 10j

Answer 1

Answer:

2i + 2j

Explanation:

Velocity of centre of mass is given by

V = (m1v1 + m2v2) / (m1 + m2)

= (2(2i - 4j) + 3(2i + 6j)) / (2 + 3)

= (4i - 8j + 6i + 18j) / 5

= (10i + 10j) / 5

= 2i + 2j