A bird of mass 0.5 kg is flying with a constant speed maintaining the
same height of 5 m. In this state if its kinetic energy and potential energy
are equal.
a) What is the potential energy of the bird?
b) What is the velocity of the bird?
Answers
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Potential energy at a height = mgh —— ( only applicable for small heights)
So PE = 0.5* 10* 5 = 25 joules
B)
1/2 * m*(v^2 ) = mgh (KE = PE)
Taking g as 10m/s^2
1/2*v^2 = 25
V^2 = 50
Velocity of bird = 5root 2m/s = 7m/s approx
So PE = 0.5* 10* 5 = 25 joules
B)
1/2 * m*(v^2 ) = mgh (KE = PE)
Taking g as 10m/s^2
1/2*v^2 = 25
V^2 = 50
Velocity of bird = 5root 2m/s = 7m/s approx
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