A bird of mass 400 gm is flying horizontally at a certain height with constant accelerat ion of 5 m/s² The force exerted by surrounding air on the bird has magnitude ( g = 10m/s² )
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0.12s
0.08s
0.04s
12s
Answer :
A
Solution :
Velocity by which the ball hits the bat
v1=2gh1−−−−√=2×10×5−−−−−−−−−√ or v→1=+10m/s=10m/s .
Velocity of rebound
v2=2gh1−−−−√=2×10×20−−−−−−−−−√=20m/s or v→2=−20m/s .
F=mdvdt=m(v→2−v→1)dt=0.4(−20−10)dt=100N.
by solveing, dt=0.012 sec.
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