Question

A bird sitting on a tree top at a height of 10 m from the ground, picks up sticks lying on the ground to build a nest on the tree top. It starts picking up the sticks at 7:00 a.m. and ends up 7:10 am. During this interval it makes 5 trips up and down. Find the average speed and average velocity of the bird.​

Answer 1

$\sf{\green{\large{\underline{\dag \: {Given:}}}}}$

• A bird sitting on a tree top at a height of 10 m from the ground, picks up sticks lying on the ground to build a nest on the tree top.

• It starts picking up the sticks at 7:00 a.m. and ends up 7:10 am. During this interval it makes 5 trips up and down.

• During this interval it makes 5 trips up and down.

$\sf{\green{\large{\underline{\dag \: {To \: Find:}}}}}$

• The average speed and average velocity of the bird.

$\sf{\green{\large{\underline{\dag \: {Solution:}}}}}$

Using formula,

• S = D/T

• Avg. speed = Total distance/Total time taken

Where,

Total distance = 2*10*5 = 100m

Total time = (7:10 - 7:00)am = 600sec.

On putting values in the formula,we have,

Avg. speed = 100m/600sec

Avg. speed = 1/6ms^-1

Avg. speed = 0.166ms^-1

Total displacement = 0

∴ Avg. velocity = 0

Answer 2

Answer:

Given :-

A bird sitting on a tree top at a height of 10 m from the ground, picks up sticks lying on the ground to build a nest on the tree top.

• It starts picking up the sticks at 7:00 a.m. and ends up 7:10 am. During this interval it makes 5 trips up and down.

• During this interval it makes 5 trips up and down.

† To Find :-

• The average speed and average velocity of the bird.

†Solution :-

Using formula,

Speed = Distance / Time

Avg. speed = Total distance/Total time taken

Where,

Total distance = 2x10x5 = 100m

Total time = (7:10 - 7:00)am = 600sec.

On putting values in the formula,we have,

Avg. speed = 100m/600sec

Avg. speed = 1/6ms^-1

Avg. speed = 0.166ms^-1

Total displacement = 0

∴ Avg. velocity = 0 m/s

Hope it helps you :)