Question

A bird was flying in a line parallel to the ground from North to South at a height 2000m. Tom standing in a middle of the field first observed in the north at an angle of 30 digree. After 3min he again observed it in the south at an angle of 45digree find the speed of the bird in kilometer per hour. √3=1.73​

Answer 1

Step-by-step explanation:

Answer:109.20

Step-by-step explanation:a bird is flying to north at an angle of elevation of 30°.

Using tan 30°=opp/adj

=1/√3=2000/BC

BC=2000√3m-------------(1)

Now, the bird fly to south at an angle of elevation of 45°

= tan45°=opp/adj

=1=2000/CD

=CD=2000m----------------(2)

Therefore,distance=BC+CD

2000√3+2000 =2000(√3+1)m

But we want the answer in km

2000(√3+1)/1000 = 2(√3+1)km

Bird takes 3min=3/60hr

Therefore,speed=distance/time

=2(√3+1)/3/60

=2(√3+1)×60/3

=20(2√3+2)

=40√3+40. (√3=1.73)

=40×1.73+40

=69.20+40

=109.20km/hr

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Answer 2

Hope it help you in your answer !!!