Question

a bird was flying in line parallel to the ground from north to south at a height of the 2000 m from the middle of the field first observe the bird in the north at an angle of 30° after 3 min he again observe it in such at an angle of 45° find the speed of the bird in km/hrs​

Answer 1

Answer:

109.28 km/hr

Step-by-step explanation:

tan 30°$= \frac{x}{2000}$

x = 3464.10 m

tan 45° = $\frac{y}{2000}$

y = 2000 m

The total distance travelled by bird = 3464.1 + 2000 = 5464.1 m = 5.464 km

Time taken = 3 min = 0.05 hour

speed $= \frac{distance}{time } = \frac{5.464}{0.05}$   = 109.28 km/hr