Question

A birthday balloon is filled to a volume of 1.5L of helium gas in an
air-conditioned room at 293K. The balloon is taken outdoors on a
warm day where the volume expands to 1.55L. Assuming the
pressure and the amount of gas remain constant, what is the air
temperature outside in Celsius?​

Answer 1

Answer:

20.66667℃ or 20.67℃

Explanation:

Given:

V1 = 1.5 L

V2 = 1.55 L

T1 = 293 K

T2 = ?

Convert Kelvin to Celcius:

℃ = K – 273

    = 293 – 273

℃ = 20℃

T1 = 20℃

Solve:

V1T2 = V2T1

T2 = V2T1/V1

   = [(1.55 L)(20℃)]  / 1.5 L

T2 = 20.66667℃ or 20.67℃

Hope it helps y'all

Answer 2

Given:

The volume of helium in the birthday balloon is 1.5l

The room is air-conditioned at 293K

The volume expands to 1.55l in heat

Assuming that the amount of gas remains constant to the pressure.

To Find:

The temperature of the air outside in Celsius

Solution:

Let the volume of helium in the air-conditioned room be V1 and the volume outside be V2.

Let the temperature of the air-conditioned room be T1 and the temperature outside be T2.

Firstly, we convert Kelvin into Celsius

°C = K - 273

    = 293 - 273

    = 20°C

∴ T1 = 20°C

Now,

V1T2 = V2T1

T2 = V2T1/V1

We substitute the values,

    = [(1.55l)(20°C)]/1.5l

    = 20.66667°C

    = 20.67°C

Therefore, the T2 i.e., the temperature outside in Celsius is 20.67°C