A bis starting from rest moves with a uniform acceleration of 0.1m/s2 for 2 minutes find the speed acquire and the distance travelled
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Answered by
1
u=0
(acceleration)d=.1m/s2
t=2 min
v=U+ at
v=0+.1*2*60
v=12.0
=12m/s (speed)
s= Ut +1/2at^2
0*2 + 1/2*0.1*120*120
0+60*120*0.1
720.0
therefore s=720m
(acceleration)d=.1m/s2
t=2 min
v=U+ at
v=0+.1*2*60
v=12.0
=12m/s (speed)
s= Ut +1/2at^2
0*2 + 1/2*0.1*120*120
0+60*120*0.1
720.0
therefore s=720m
MDSK:
nyc
Answered by
1
u=o. a=0.1m/s². t=2min.
s=ut +1/2at²
s=o*120+1/2 *0.1*(120)²
s=1/2*0.1*(120)²m
now calculate this....
after calculating distance u can easily calculate speed by using formula
v²-u²=2as
s=ut +1/2at²
s=o*120+1/2 *0.1*(120)²
s=1/2*0.1*(120)²m
now calculate this....
after calculating distance u can easily calculate speed by using formula
v²-u²=2as
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