Question

A bit of help needed with trig

Answer 1

Step-by-step explanation:

1) Since triangle QTS is a right angled triangle at T,

Using trigonometric ratios,

sin S = TQ/QS

sin 60° = TQ/25

TQ = ( 25root3 ) / 2

TQ = 21.63 cm (approx)

2) Since triangle PTQ is a right angled triangle at T,

Using trigonometric ratios,

tan Q = PT/TQ

Also, since PQT, TQS and SQR are linear paired angles,

their sum is 180°

PQT + 30° + 90° = 180°

PQT = 60°

Therefore,

tan 60° = PT/21.63

root 3 = PT/21.63

PT = 37.5 cm

3) PR = PQ + QR

Since triangle PTQ is a right angled triangle at T,

Using trigonometric ratios,

sin Q = PT/PQ

sin 60° = 37.5/PQ

PQ = 43.35 cm (approx)

Since triangle SQR is a right angled triangle at Q,

Using trigonometric ratios,

tan S = QR/QS

tan 45° = QR/25

QR = 25 cm

Therefore,

PR = 43.35 + 25

PR = 68.35 cm (approx)

Answer 2

Answer:

Step-by-step explanation: