Question

A bivalent metal has in equivalent mass of 32. The molecular mass of the metal nitrate is
(a) 182
(b) 168
(c) 192
(d) 188

Answer 1

answer : option (d) 188g/mol

explanation : equivalent mass of metal = 32

metal is bivalent so, atomic mass of metal = equivalent mass × 2 = 32 × 2 = 64 g/mol

now, molar mass of metal nitrate , $M(NO_3)_2$ = atomic mass of M + 2 × (atomic mass of N + 3 × atomic mass of O)

= 64 g/mol + 2 × (14 g/mol + 3 × 16 g/mol)

= (64 + 28 + 96) g/mol

= 188 g/mol

hence, molar mass of metal nitrate is 188 g/mol

Answer 2

A bivalent metal has in equivalent mass of 32. The molecular mass of the metal nitrate is

(a) 182

(b) 168

(c) 192

(d) 188 ✅✅

Option D is correct.