Question

A black body at 2000 k emits maximum energy at a wavelength of 1.56 um. At what temperature will it emit maximum energy at a wavelength of 1.8 um

Answer 1

Answer:

T2 = 2066.115 K

Explanation:

T1 = 2000 K

E1 = 1.56 um

E2 = 1.8 um

T2 = ?

since,  

E1/E2 = T1^4 / T2^4

Therefore,

1.56/1.8 = (2000 / T2)^4

0.8667 = (2000 /T2)^4

(0.9648)^4 = (2000 /T2)^4

0.9648 = 2000 /T2

T2 = 0.9648 * 2000

T2 = 2066.115 K

HOPE IT HELPS YOU...

Answer 2

At 1733.3K the blackbody will emit maximum energy at a wavelength of 1.8 μm.

Given:

T1= 2000 K ,λ1 = 1.56μm and λ2 = 1.8μm.

To Find:

what temperature will it emit maximum energy at a wavelength of 1.8 um(T2)

Solution:

From Wien's Law

T1* λ1 = T2*λ2

⇒ T2 = (T1*λ1)/λ2

⇒ T2 = (2000*1.56) / 1.8

⇒ T2 =3120 / 1.8

⇒ T2 = 1733.3 K.

∴ At 1733.3K the blackbody will emit maximum energy at a wavelength of 1.8 μm.

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