Question

A black body at a temp. 227° C radiates heat energy at a rate of 20cal / m² / s. When its temp. is raised to 727° C , find the rate of heat radiated.

# Give the correct answer with explanation.
# No spam​

Answer 1

Answer:

R2′=80   cal/cm2

Explanation:

Heat energy per unit time          R=σAeT4

Thus heat energy per unit area       R′=σeT4

⟹    R1′R2′=(T1T2)4

Initial temperature of the body       T1=227oC=(227+273)K=500K

Final temperature of the body       T2=727oC=(727+273)K=1000K

∴     5R2′=(5001000)4

5R2′=16               

⟹R2′=80   cal/cm2

hope it helps ❣

consider marking me as brainleist