Physics, asked by rodz, 1 year ago

a black body at high temperatures T K radiates at the rate of E W/m^2 when the temperature falls to T/2 k, the radiated energy will be

Answers

Answered by kvnmurty
47
According to Stefan Boltzmann law the radiated energy per unit time (power) across all wavelengths from a black body at a temperature T °K is given by

        J = σ T⁴ 

   where σ = Stefan Boltzmann's constant = 5.67 * 10⁻⁸ Wb /m²/K⁻⁴

Given   J = E = σ T⁴

  When  T becomes T/2 °K,  then   J = σ T⁴/2⁴ = E/16

  So the radiated power (energy/time) will become 1/16 th of E.

kvnmurty: :-)
Answered by Anonymous
6

the radiation power become 1/16 of its original value

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