Physics, asked by etibag986, 5 hours ago

A black body calorimeter filled with hot water cools from 60°C to 50°C in 4 minutes and 40°C to 30°C in 8 minutes. The approximate temperature of surrounding is (use average method) ​

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Answered by Anonymous
0

Assuming the temperature of surrounding be t°C

CASE-1

 \frac{(60−50)}{4min}  =k(55−t)(1)

Again, CASE-2\frac{(40−30)}{8min}  =k(35−t)(2)

 \frac{(1)}{(2)}  =  \frac{ \frac{10}{4} }{ \frac{10}{8} }  =  \frac{(55 - t)}{(35 - t)}

⇒2(35−t)=55−t

⇒70−2t=55−t

⇒t=15℃

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