Question

A black body is at a temperature of 2880 K. The energy of radiation emitted by this object with wav
499 nm and 500 nm is U between 999 nm and 1000 nm is U2 and between 1499 nm and 1500r
constant b = 2.88x10mm K. Then​

Answer 1

Given:

The temperature of the body is T= 2880 K

Wein's constant b= 2.88×10⁶ nmK

To find:

Which energy radiation has more wavelength.

Solution:

The energy of radiation emitted by first is

U= 499 to 500 nm

U'= 99 to 1000nm

U"= 1499 to 1500nm

Now applying the wein's formula

λT=b

Putting the above value in the equation.

λ=2.88×10⁶/2880

λ=10³

When we compare from above energy radiation we get to know that

U'>U

So the correct answer of greater radiation is U'>U