A black body radiates 600 joules of energy per second at 280 K temperature.What will be the amount of energy radiated when temperature is 500K?
Answers
Answered by
0
Answer:
1071.4285 joules of energy per second
Explanation:
Energy radiated per second at 280K temp. = 600 joules
280K=600 joules
1 K =600/280
500K={(600/280)×500} joules per second
500K=1071.4285 joules per second .
Answered by
1
Answer:
Explanation:
Q ∝ t^4
q1/q2 =(t1/t2)^4
600/q2=(280/500)^4
600/q2=0.01
q2=60000j
=60kj
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