Question

A blackboard is 27dm 7cm long and 21dm 5cm broad. What will be the cost of painting​

Answer 1

Answer:

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Cost of painting = ₹ 7,12,425 .

\bold{\underline{\underline{Step\:-\:by\:-\:step\:explanation:}}}

Step−by−stepexplanation:

Given :

•Length of the black board is 17 dm 7 cm

•Breadth of the black board is 11 dm 5 cm

•Cost of painting the blackboard is 35 paise per square centimeter.

To find :

•Cost of painting the blackboard.

Solution :

Since the values are given in decimetre, we will first convert the units.

For length :-

1 dm = 10 cm

•°• 17 dm = 17(10) = 170 cm

Length of the blackboard = 170 + 7

•°• Length (l) = 177 cm

For breadth :-

\rightarrow→ \bold{Breadth=11(10)}Breadth=11(10)

\rightarrow→ \bold{Breadth=110}Breadth=110

•°• Breadth(b) = 110 + 5 = 115 cm

So now we have the length and breadth of the black board in same unit. So let's find the area of the blackboard.

Area of blackboard :-

\rightarrow→ \bold{Area\:=\:length\times\:breadth}Area=length×breadth

Block in the values,

\rightarrow→ \bold{Area\:=\:177\times\:115}Area=177×115

\rightarrow→ \bold{Area\:=20355}Area=20355

•°• Area = 20355 cm²

Now, to find the cost.

Cost required will be area of the blackboard times cost of painting the blackboard per square centimeter

Cost of painting,

\bold{Area\:of\:blackboard\times\:rate\:per\:square\:centimeter}Areaofblackboard×ratepersquarecentimeter

\rightarrow→ \bold{20355\times\:35}20355×35

\rightarrow→ \bold{712425}712425

•°• Cost of painting the blackboard at the rate of 35 paise per square centimeter is ₹ 7, 12, 425.

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