Question

A blacksmith has five iron articles Arun, Baby, Chirak, Duke and
Edwin each having a different weight.
i) Arun weights twice as much as Baby
ii) Baby weights four-and-a half times as much as Chirak
ii) Chirak weights half as much as Duke
iv) Duke weights half as much as Edwin
v) Edwin weights less than Arun but more than Chirak
Which is the lightest in weight?
Select one:
O
a. Arun
b. Baby
c. Chirak
d. Duke​

Answer 1

Answer:

$\huge{\underline{\rm{C) \: Chirak}}}$

Step-by-step explanation:

For our convenience, let's take the above given names of Arun, Baby, Chirak, Duke and Edwin as A, B, C, D and E respectively.

Given data,

• Arun weights twice as much as Baby.

$\boxed{\bf \longrightarrow A = 2 B}$

• Baby weights four-and-a half times as much as Chirak.

$\boxed{\bf \longrightarrow B =4 \dfrac{1}{2}C}$

• Chirak weights half as much as Duke.

$\boxed{\bf \longrightarrow C = \dfrac{1}{2}D}$

• Duke weights half as much as Edwin

$\boxed{\bf \longrightarrow D = \dfrac{1}{2}E}$

• Edwin weights less than Arun but more than Chirak.

$\boxed{\bf \longrightarrow A> E > C}$

After taking all the data together, we get -

• C < E
• C < A
• C < B
• C < D

Therefore, Chirak is the lightest in weight.