a blacksmith have a big iron ball of diameter 36cm. he first formed four identical cylindrical rod out of this ball for some construction work when he finishes his work with the cylindrical rod he again mixed all the iron rod and formed some identical small balls each of radius 9 cm
(2) if the diameter of each cylinder formed by him is 12cm then height of each of them is
Answers
Answer:
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Explanation:
Given :-
Diameter of iron ball = 36 cm.
Radius of small balls = 9 cm.
To Find :-
Number of small ball formed by blacksmith ?
Solution :-
Let us assume that, n number of small ball formed by blacksmith.
so,
→ Volume of iron ball = n * volume of each small ball .
→ (4/3) * π * (R)³ = n * (4/3) * π (r)³
(4/3) and π will be cancel from both sides,
→ (R)³ = n * (r)³
→ (36/2)³ = n * (9)³
→ (18)³ = n * (9)³
→ 18 * 18 * 18 = n * 9 * 9 * 9
→ n = 2 * 2 * 2
→ n = 8 (Ans.)
Hence, the number of small ball formed by blacksmith are 8 .
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