Question

a blacksmith have big iron ball of diameter 36 cm he formed four identical cylindrical rods out of thhe ball for some construction work when he finished his work with this he again mixed all the iron rod and formed some identical small balls each of radius 9 cm now tell the number of samall ball formed by blacksmith?
i) 6
ii) 10
iii) 8
iv) 16​

Answer 1

8 is right answer

hope its useful

Answer 2

Given :-

• Diameter of iron ball = 36 cm.
• Radius of small balls = 9 cm.

To Find :-

• Number of small ball formed by blacksmith ?

Solution :-

Let us assume that, n number of small ball formed by blacksmith.

so,

→ Volume of iron ball = n * volume of each small ball .

→ (4/3) * π * (R)³ = n * (4/3) * π (r)³

(4/3) and π will be cancel from both sides,

→ (R)³ = n * (r)³

→ (36/2)³ = n * (9)³

→ (18)³ = n * (9)³

→ 18 * 18 * 18 = n * 9 * 9 * 9

→ n = 2 * 2 * 2

→ n = 8 (iii) (Ans.)

Hence, the number of small ball formed by blacksmith are 8 .

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