Question

A blacksmith have big iron ball of diameter

36cm. He first formed four identical

cylindrical rod out of this ball for some

construction work. When he finished his

work with the cylindrical rod, he again

mixed all the iron rod and formed some

identical small balls, each of radius 9cm.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given :-

• Diameter of iron ball = 36 cm.
• Radius of small balls = 9 cm.

To Find :-

• Number of small ball formed by blacksmith ?

Solution :-

Let us assume that, n number of small ball formed by blacksmith.

so,

→ Volume of iron ball = n * volume of each small ball .

→ (4/3) * π * (R)³ = n * (4/3) * π (r)³

(4/3) and π will be cancel from both sides,

→ (R)³ = n * (r)³

→ (36/2)³ = n * (9)³

→ (18)³ = n * (9)³

→ 18 * 18 * 18 = n * 9 * 9 * 9

→ n = 2 * 2 * 2

→ n = 8 (Ans.)

Hence, the number of small ball formed by blacksmith are 8 .

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