A blacksmith, Sujan made a pillar which consists of a cylindrical portion 2.8 m high and
20 cm in diameter and a cone 4.2 cm high is surmounting it. Find the weight of the pillar, 1 cm of iron weighs 7.5 grams.
Answers
Answer
693 kg
Step-by-step explanation:
Given,
An iron pillar consists of a cylindrical portion and a cone mounted on iThe height of the cylindrical portion of the pillar, H=2.8 m=280 cm
The height of the conical portion of the pillar, h=42 cm
The diameter of the cylindrical portion of the pillar = diameter of the circular base of cone =D=20 cm
The radius of the circular base of cylinder/ cone r=
2D =10 cm
Now,
Volume of the pillar, (V)= Volume of the cylindrical portion of pillar + volume of the conical portion of the pillar.
→V=πr 2 H+ 31
πr 2 h
→V=(
7/22 ×10
2 ×280+ 31 × 7/22 ×10
2 ×42) cm 3.
→V=(22×100×40+22×100×2) cm
3
→V=(88000+4400) cm
3
→V=92400 cm
3
Hence, volume of iron pillar is 92400 cm
3
Given,
Weight of 1 cm
3
iron =7.5 gm.
Hence, weight of 92400 cm
3
iron =7.5×92400 gm.
=693000 gm.
=693 Kg. ∵1Kg=1000 gm.
Hence, the weight of iron pillar is 693 Kg.
hope you got the answer