A blind person after walking 10 steps in one direction, each of length 80cm, truns randomly to the left or to the right by 90°. After walking a total of 40 steps the maximum possible displacement of the person from his starting position could be what
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Consider the above diagram
The starting position of the person is c
Then he walk 10 steps(8m)
And then towrds left with 30 footsteps (24m) (because the total is given 40 steps
Then by pythagoras theorem
Ac^2=Ab^2+Bc^2
=64+576
=640
Ac=sqrt(640)
=25.30
The starting position of the person is c
Then he walk 10 steps(8m)
And then towrds left with 30 footsteps (24m) (because the total is given 40 steps
Then by pythagoras theorem
Ac^2=Ab^2+Bc^2
=64+576
=640
Ac=sqrt(640)
=25.30
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Max displacement =√640000+160000=√8multiply√10000=100√8
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