Question

A block 'A' of charge q is fixed and second block of mass m and charge q, is allowed to free on the floor findout the range of q,for which the particle is at rest. Ex.4 A.q m.az fixed Sol Maximum friction = umg

Answer 1

Answer:

Explanation:

untill friction force not equal to coulomb force second body will not move so μmg=14πε0q1q2r2q2= μmg4πε0r2/q1so range of 0  to ∣∣ μmg4πε0r2/q1∣∣