A block a of mass 2 kg rests on another block b of mass 8 kg which rests on a horizontal floor. the coefficient of friction between a and b is 0.2 while that between b and floor is 0.5. when a horizontal force 25 n is applied on the block b, the force of friction between a and b is:
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Block B together with block A is lying on rough surface with coefficient of friction=0.5.
(coefficient of friction) x (mA+mB)x g
=0.5x10x10=50 N.
So frictional force= 0
(coefficient of friction) x (mA+mB)x g
=0.5x10x10=50 N.
So frictional force= 0
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