Physics, asked by Nike69181, 11 hours ago

A block a of mass 2m is placed on another block b of mass 4m which in turn is placed on a fixed table. The two blocks have same length 4d and they are placed as shown in fig. The coefficient of friction (both static and kinetic) between the block b and table is |li. There is no friction between the two blocks. A small object of mass m moving horizontally along a line passing through the centre of mass (com), of the block b and perpendicular to its face with a speed v collides elastically with the block b at a

Answers

Answered by archanaacharya486
0

Answer:

The slippage between the bottom block and the table will occur first. Both block will slide on the table when the force is greater than 20.55g.

The slippage between the bottom block and the table will occur first. Both block will slide on the table when the force is greater than 20.55g.45g*0.6 = 27 g

The slippage between the bottom block and the table will occur first. Both block will slide on the table when the force is greater than 20.55g.45g*0.6 = 27 g68.5g*0.3 =20.55g

The slippage between the bottom block and the table will occur first. Both block will slide on the table when the force is greater than 20.55g.45g*0.6 = 27 g68.5g*0.3 =20.55g(b) If the static friction between the bottom is 0.3942 or greater, the slippage between the two blocks will occur first.

The slippage between the bottom block and the table will occur first. Both block will slide on the table when the force is greater than 20.55g.45g*0.6 = 27 g68.5g*0.3 =20.55g(b) If the static friction between the bottom is 0.3942 or greater, the slippage between the two blocks will occur first.27g/68.5g = 0.3942

Similar questions