A block A weighing 100N is pulled up a slope of length 5m by a means of a constant force of 100N what is the increase in potential energy of block A
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Answered by
23
u = mgh
w = mg
100= m×10 , m = 10kg
u = 10×10×5 = 500joule...
w = mg
100= m×10 , m = 10kg
u = 10×10×5 = 500joule...
Answered by
7
500 N m
Given -
m = 100 N (Can be written as 10 kg as 100 N = 10 kg)
h = 5 m
g = 10 m/s2
Solution -
P.E = mgh
P.E = 10 kg * 10 m/s2 * 5m
P.E = 500 Nm
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