Question

a block attached to a spring oscillates in a simple harmonic motion along the xaxis. limits of motion are from x=10 to x=50cm.lt goes from one extreme to other in 0.25s.find amplitude and frequency.​

Answer 1

Given:-

limits of motion from x=10 cm to 50 cm

time taken to go from one end to other end, t=0.25 s

To Find:-

Amplitude and frequency

Explanation:-

Amplitude is defined as maximum distance travelled by block from its mean position.

$\text{mean position of the block}=\dfrac{50+10}{2}=30cm\\\\\Rightarrow\text{Amplitude, }A=30-10=20cm$

$\text{Now,}\\\\\text{Total time taken by the block to complete one cycle of oscillation, T}=2\times0.25=0.5s\\\\\Rightarrow\text{Frequency, f}=\dfrac{1}{T}=\dfrac{1}{0.5}=2Hz$

Answer 2

Answer:20 cm,4 Hz

Explanation: