Question

A block attached to a spring, pulled by a constant horizontal
force, is kept on a smooth surface as shown in the figure.
Initially, the spring is in the natural state. Then the maximum
positive work that the applied force F can do is : [Given that
spring does not break]​

Answer 1

Answer:

$\frac{F^2}{2k}$

Explanation:

1) Let the maximum extension in spring be 'l'.

We know,

Maximum positive work applied force F can do when, Block is moved to the farthest distance.

2) When extension in spring is 'l',Block has moved farthest distance .

$F=kl \\ \\ =>l=\frac{F}{k}$

3)  Maximum work is done when complete potential energy of Spring goes to Work done by 'F'.

Kinetic Energy is 0 as initial and final velocity will be 0.

$W_F=\frac{1}{2}kl^2\\ \\=\frac{1}{2}k(\frac{F}{k})^2\\ \\=\frac{F^2}{2k}$

Hence, Maximum work done is

$\boxed{\frac{F^2}{2k}}$

Answer 2

Answer:

hope it helps u sir ❤❤❤❤❤❤❤