Question

A block ‘C’ of mass m is projected with a velocity v as shown. The ground is smooth but there is friction between A and B. If collision is elastic, the total energy dissipated in friction  is (Assume that A does not fall off B)​

Answer 1

Answer:

In case of elastic collision.....

• No loss of K.E
• Momentum is conserved
• Total energy is conserved

Answer 2

Answer:

The energy dissipated is 1/2mv²

Explanation:

Given

Mass of block=m

Velocity of a block=v

Elastic collision conserves K.E

To find energy dissipated in friction=kinetic energy(K.E)

Solution:

Kinetic energy is given as,

$K.E=1/2mv^{2}$

⇒1/2mv²

Therefore, the total energy dissipated in friction is 1/mv².