Question

A block exerts a pressure of 80 Pa on the floor. If the weight of the block is 20 N, what is the area of the block in contact with the floor?​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:-

THEY HAVE GIVEN PRESSURE IS(P) = 80 Pa

ALSO THEY HAVE INDIRECTLY GIVEN THE FORCE AS THE WEIGHT OF THE BLOCK (F) = 20 N

SO THE AREA(A) = ?

WE KNOW PRESSURE =  FORCE / AREA

= P = F/A

SO AREA = FORCE / PRESSURE

= A = F/P

= A = 20 / 80

= A = 0.25 m²

SO THE AREA OF THE BLOCK IN CONTACT WITH THE FLOOR IS 0.25 m²

Explanation :-

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