Question

A block falls from a table 0.6 m high it lands on an ideal massless vertical spring with a force constant of 2.4

Answer 1

mg(dh) = 0.5k(dx)^2

Where,

m = block mass,

dh = difference between the table height

And,

The block height at maximum spring compression = 0.6 - 0.10 = 0.5 m, g = 9.8 m/s^2, k = 2.4kN/m = 2400 N/m, 

dx = spring compression distance = 0.25 - 0.10 = 0.15 m 

m(9.8)(0.5) = 0.5(2400)(0.15)^2 
m = 5.5 kg

Answer 2

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