A block hangs from a string wrapped on a disc of radius 20 cm free to rotate about its axis which is fixed in a horizontal position. If the angular speed of the disc is 10 rad/s at some instant, with what speed is the block going down at that instant?
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DEAR FRIEND,
When the string passes through the disc and the velocity of the point of the string in contact with the disc, is the same as its velocity along the whole string, as long as there exists no slipping between the surface of the disc and the string.
Thus, by using the formula : -
Linear Velocity = Radius × Angular Velocity
We get,
=> Velocity of the block = 20 cm × 10 rad/s
=> Velocity of the block = 200 cm/s
= 2 m/s
This is our answer.
I HOPE THIS HELPS MY FRIEND!!!
HAVE A GREAT DAY!!!!
When the string passes through the disc and the velocity of the point of the string in contact with the disc, is the same as its velocity along the whole string, as long as there exists no slipping between the surface of the disc and the string.
Thus, by using the formula : -
Linear Velocity = Radius × Angular Velocity
We get,
=> Velocity of the block = 20 cm × 10 rad/s
=> Velocity of the block = 200 cm/s
= 2 m/s
This is our answer.
I HOPE THIS HELPS MY FRIEND!!!
HAVE A GREAT DAY!!!!
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