Question

A block is displacement from ( 1 m, 4m, 6 m) to (2 ICAP + 3 J cap + 4 cap) metres under a constant force f = (6 ICAP - 2j cap + K cap) Newton's. find the work done by this force

Answer 1

I cap = x coordinate
J cap = y coordinate
K cap = z coordinate

displacement = (x2-x1) + (y2 -y1) + (z2 - z1)
= (2-1) I cap + (3-4) J cap + (4-6) K cap
= 1 I cap - 1 J cap - 2 K cap

Work = force * displacement
= (1 I cap - 1 J cap - 2 K cap) * (6 ICAP - 2j cap + K cap)

= 6 + 2 - 2
= 6 I cap
= |6|
= 6 J ( 6 Joules )