Question

a block is dragged on a smooth plane with the help of a rope which moves with velocity v. the horizontal of the block is (whre theta is angle between horizontal and the rope)
1.v costheta
2. v costheta
3. v sin theta
4. v​

Answer 1

Answer:

the correct ans is c

Explanation:

it is vsin(theta) as the component is vsin(theta)

Answer 2

Explanation:

x2=y2+d2

⇒2xdxdt=2ydydt

⇒dydt=(xy)(dxdt)=vsinθ

OR

Component of velocity along string must same so

vMcosθ(90−θ)=v⇒vM=vsinθ