Question

a block is dragged on a smooth plane with the help of a rope which moves with velocity v. the horizontal of the block is (whre theta is angle between horizontal and the rope)
1.v costheta
2. v costheta
3. v sin theta
4. v

Answer 1

v=dl/dt

x^2 + y^2 =l^2

w.r.t t differentiation

2x dx/dt +0 =2l dl/dt

x dx/dt= l dl/dt , dx/dt= l/x dl/dt

V=v/x/l

V=v/sin theta

So the answer would be (3) v sin theta

Answer 2

Answer:

This is the answer in picture

Explanation: