A block is given an initial velocity of 5.0 m/s in upward direction on a friction less 30.0 degree incline. How far up the incline does the block slide before coming to rest ? (Take g = 10 m/s).
A. 5.0m
B. 7.5m
C. 10m
D. 2.5m
Answers
Answered by
1
Answer:
2.5 m
Explanation:
Answered by
0
Answer:
Option (d) is correct
Explanation:
Initial velocity u = 5 m/s (upward along the plane)
The retarding force on the body is
F = - mgsinθ
m a = - m g sinθ
a = - g x sin30°
= - 10 x 1/2
= - 5 m/s²
v² - u² = 2as
0 - (5)² = - 2 x 5 x s
- 25 = -10 s
∴ s = 2.5 m
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