Question

A block is given an initial velocity of 5m/s in upward direction on a friction less than 30 degree incline how far up the incline does the block slide before coming to rest

Answer 1

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Explanation:

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Answer 2

A block is given an initial velocity of 5 m/s up a frictionless incline of angle 30°. How far up the incline does the block slide before coming to rest ?

solution : initial velocity of block, u = 5 m/s

finally, block comes to rest, so final velocity of block, v = 0 m/s

component of acceleration due to gravity along plane, a = gsin30° [ it is the acceleration acting on block ]

now, using formula, v² = u² + 2as

⇒0 = (5)² + 2gsin30° × s

⇒0 = 25 + 2 × 10 × 1/2 × s

s = -2.5 m [ here negative sign indicates that the block is just below of its frame of reference. in short, it is moving downward along plane ]

Therefore the distance covered by block along plane before comes to rest is 2.5 m.

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