A block is hung in equilibrium,with spring of 60cm and it is stretched 9 cm.the spring is cut in two parts of 40&20 cm and block is hung such that it is parallel to horizontal,what is the new stretch length.
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force F=k.9
after cutting the spring new force..
F'=(k1+k2)x
we know that this new force is equal to the force that was before. because it is the weight of block
9k=(k1+k2).x
9k=(3k/2+3k).x
x=2cm
after cutting the spring new force..
F'=(k1+k2)x
we know that this new force is equal to the force that was before. because it is the weight of block
9k=(k1+k2).x
9k=(3k/2+3k).x
x=2cm
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Explanation:
FORCE 'F'= K.9
AFTER CUTTING THE SPRING NEW FORCE..
F'=(K1+K2)x
WE KNOW THAT THIS NEW FORCE IS EQUAL TO THE FORCE WHICH WAS BEFORE.
BECAUSE IT IS THE WEIGHT OF BLOCK.
9K=(K1+K2)*x
9K=(3K/2+3K)*x
x=2 cm
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