Question

A block is in equilibrium. The value of F in the
figure is (u < tan o)
F
a
0
7
(1) mg sine
(2) 2(mg sino + u mgcos e)
(3) 3(mg sino + u mgcos e)
(4) Zero​

Answer 1

Answer:

Friction force by the inclined plane is =μmgcosθ=mgsinθ up the inclined plane since the block does not slide.

Normal force perpendicular to inclined plane is mgcosθ.

So, Total force is vector sum of two forces is equal to mg.

N=mgcosθ, f

s

=mgsinθ

R

2

=N

2

+f

s

2

⇒R=mg