Question

A block is kept on a frictionless inclined surface with angle of inclination 'α'. The incline is given an acceleration 'α' to keep the block stationary. Then a is equal to



(1) g



(2) g tan α



(3) g/tan α



(4) g cosec α

Answer 1

Explanation:

we have to take the components of a also as block is moving with a horizontally and that a is taken due to the 90-a + a= 90 and another a + sone angle equals 90°. hope it hepls..