A block is kept on a horizontal surface of dimension 0.5 m × 0.6 m. If the pressure exerted by the block on the horizontal surface is 3 × 104 Pa, then mass of the block is [Take g = 10 m/s2]
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it's 900kg
see first we will find area =0.5×0.6=0.3m^2
then we have pressure so let's find force ..
P=F/A
3×10^4=W/0.3
W=3×10^4×0.3=0.9×10^4kg
W=mg
9/10×10^4 =m×10
9/10×10000=m×10
9/1000=m10
9/1000/10=m
900kg=m
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hey are u from aakash.. institute ...u also asked questions related them...
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