Physics, asked by kskpradyu, 9 months ago

A block is kept on a horizontal surface of dimension 0.5 m × 0.6 m. If the pressure exerted by the block on the horizontal surface is 3 × 104 Pa, then mass of the block is [Take g = 10 m/s2]

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Answered by pardhupaddu
3

Answer:

the solution for the given problem is solved above

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Answered by Dɪʏᴀ4Rᴀᴋʜɪ
14

hey are u from aakash.. institute ...u also asked questions related them...

it's 900kg

see first we will find area =0.5×0.6=0.3m^2

then we have pressure so let's find force ..

P=F/A

3×10^4=W/0.3

W=3×10^4×0.3=0.9×10^4kg

W=mg

9/10×10^4 =m×10

9/10×10000=m×10

9/1000=m10

9/1000/10=m

900kg=m

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hey are u from aakash.. institute ...u also asked questions related them...

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