Question

a block is kept on a rough inclined plane with angle of inclination theta the graph of net reaction R v/s is​

Answer 1

Answer:

The normal reaction is N=mgcosθ. cosθ will vary from 1 to 0 as the θ vary from 0 to π. So the N will be represented by curve (2).

Now, f

L

=μN and μ<1, so the f

L

will follow all the same trend as N with a reduced amplitude. So the curve no (3).

The net downward force is given by:

F=(mgsinθ−f

L

). When the block will cross the limiting friction then it will start moving and the frictional force will be constant. So the second term in the bracket will be constant. So f

L

will follow the nature of a sinθ curve with a origin shift to negative y-axis. So the curve no (1)

solution