Question

A block is moving on a rough horizontal
surface with valacity 'V'. The stopping
distance will be directly proportional to​

Answer 1

Explanation:

Since a block is moving on a rough surface

so its stopping distance will be directly proportional to v^2

let initial velocity = u

final velocity = u^2

We know at end of the distance velocity will be zero

so,

v2 = u2 + 2as

s = distance

here a will be negative

02 = u2 + 2(-a)s

s = u2/a

s is proportional to u2

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