Question

A block is of mass m placed on a rough inclined plane and the block is at rest on the inclined place
Find the force exerted by the inclined plane on the block​

Answer 1

Answer:

ans. is mg costheta √(1+mu^2)

Answer 2

Answer:

The contact force here is friction.

The contact force here is friction.Intitially static friction would be there which would be equal to mgsinθ ,as angle of inclination increases sinθ will increase.It will increase till it reaches its maximum value i.e umgcosθ (max static friction) .after that it will remain same i.e umgcosθ but

tic friction) .after that it will remain same i.e umgcosθ but θ will continue to increase as a result cosθ would decrease decreasing the friction applied .

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