Physics, asked by krishnanrnair7832, 10 months ago

A block is on a horizontal slab, which is moving horizontally with a simple harmonic motion of frequency, two oscillations per second. The coefficient of static friction between block and slab, is 0.50. How great can the amplitude be, if the block does not slip along the slab ?

Answers

Answered by Dhruv4886
9

The maximum amplitude for the block does not slip into the slab is 0.0311 m.

Given-

  • Coefficient of static friction between block and slab = 0.50
  • Frequency = 2

We know that w = 2πf = 2 × 3.14 × 2 = 12.56 rad/sec

From the attached figure we can say that

N -mg = 0

N = mg

For SHM

a = -Aω² cos ωt

So, a max will be Aω²

It is the limiting case for the block

From the figure- fs = ma

fs = fs max =μs N = μs mg and

a = Aω². So

μs mg = A max ω²

A max = (0.5)(9.8)/(12.56)²

A max = 0.0311 m

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Answered by NimishM
1

Answer:

Explanation:

here's a detailed explantion ..............

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