Physics, asked by anmolvoltp784kl, 9 months ago

A block is placed on an inclined plane of angle 30o with the horizontal and 6.4m long. Find the time taken by a block to slide down to the bottom, if the coefficient of friction between the block and surface of inclined plane is 0.2 (Take g = 10m/s2 )

Answers

Answered by dheerajbaranwal2016
0

Answer:

√3.91 seconds = 2 seconds

To get the solution

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Answered by Mɪʀᴀᴄʟᴇʀʙ
9

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A block is placed on an inclined plane of angle 30o with the horizontal and 6.4m long. Find the time taken by a block to slide down to the bottom, if the coefficient of friction between the block and surface of inclined plane is 0.2 (Take g = 10m/s2 ).

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From FBD acceleration can be claculated as

a=mmgsinθ−μmgcosθ=gsinθ−μgcosθ

⟹a=3.267m/s2

from.equation. of  .motion  s=ut+21at2,

where .  u= initial  . velocity=0

6.4=21×3.267×t2

⟹t=1.979

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