Question

A block is projected along a rough horizontal road with a speed of 10 m/s. If the coefficient of kinetic friction is 0.10, how far will it travel before coming to rest ?

Answer 1

Since,

μ = ma/mg.

∴ μ = a/g

⇒ a = μg

∴ a = 0.10 × 10

∴ a = 1 ms⁻²

Since, the body is stopping, therefore, acceleration = - 1 ms⁻²

Now, Final velocity (v) = 0

Initial velocity (u) = 10 ms⁻¹.

∴ v² - u² = 2aS

∴ (0)² - (10)² = 2(-1)S

∴ S = 50 m.

Hope it helps.