Physics, asked by pranisha2002, 10 months ago

A block is pushed up a frictionless 30 incline by an applied force as shown. If F = 25 N and M = 3.0 kg, what is the magnitude of the resulting acceleration of the block ? (NO SPAM)

Answers

Answered by Shruti1357
4

The force required to accelerate the body kept on the tilted plane should be more than the gravitational force, which moves the body down the incline. Therefore, the applied force remaining after overcoming the resistance force is proportional to the resulting acceleration of the body. Mathematically:

hope it helps you..

Answered by ParvezShere
2

The magnitude of the resulting acceleration of the block is -2.3 m/s².

Given:

A block is pushed up a frictionless 30° incline by an applied  F = 25 N and M = 3.0 kg.

To Find:

Magnitude of the resulting acceleration of the block

Solution:

Given data,

Inclination ∅ = 30°

Force F = 25N

Mass of the block M = 3 Kg

Acceleration due to gravity g = 9.8 m/s²

Resulting acceleration of the block a.

Using Newton's Second Law,

∑F = Ma

⇒Mgsin∅ - Fcos∅ = Ma

⇒3*9.8*sin30 - 25*cos30 = 3a

3*9.8*\frac{1}{2} - 25*\frac{\sqrt{3} }{2} = 3a

⇒14.7 - 21.6 = 3a

⇒ 3a = -6.9

⇒ a = -2.3 m/s²

Therefore, the magnitude of the resulting acceleration of the block is -2.3 m/s².

#SPJ2

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