A block is sliding down on a rough inclined plane of
angle of inclination 0, with constant velocity. The
force of friction between the block and inclined
plane is (coefficient of friction between block and
inclined plane is u)
(1) umg
(2) mgcose
(3) mgsino
(4) umgsine
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2
Answer:umgcos@
Explanation:
As the block is sliding down the inclined plane there will be a normal force acting on the block by the plane... Like given in the picture.
But the options you had give doesn't contain this I think you have forgotten to write "u" In option 2
Then it becomes umgcos@.
Thank you
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